二维数组

xt6_1

/*p105 4.12*/
#include <stdio.h>
main()
{
int m[][3]={1,2,3,4,5,6,7,8,9,10,11,12};
printf("%d\n",a[2][1]);
}

xt6_2

/*p105 4.12*/
#include <stdio.h>
main()
{
int m[4][3]={{1,2},{3,4},{5,6,7},{8,9}},i,j;
for(i=0;i<4;i++)
for(j=0;j<3;j++)
printf("m[%d][%d]=%d\n",i,j,m[i][j]);
}

xt6_3

/*p105 4.13*/
#include <stdio.h>
main()
{
int m[3][3]={{1},{2},{3}};
static int n[3][3]={1,2,3};
printf("%d\n",m[2][0]+n[0][2]);
}

xt6_4

/*p109 4.34
1 2 3 4
2 2 5 6
3 5 3 7
8 6 7 4 */
#include <stdio.h>
main()
{
int a[][4]={1,2,3,4,2,2,5,6,3,5,3,7,8,6,7,4};
int i,j,found=0;
for(j=0;j<4;j++)
{
if(found) break;
for(i=0;i<4;i++)
if(a[i][j]!=a[j][i])
{
found=1;
break;
}
}
if(found) printf("不对称\n");
else printf("对称\n");
}

xt6_5

/*z231 21*/
#include <stdio.h>
main()
{
char a[][5]={"ABCD","1234","abcd","5678","EFGH"};
int i;
for(i=0;i<3;i++)
printf("%s",a[i]);
printf("\n");
}

xt6_6

#define N 6
#include <stdio.h>
main()
{
int i,j,a[N][N];
for(i=0;i<N;i++) a[i][0]=a[i][i]=1;
for(i=2;i<N;i++)
for(j=1;j<i;j++)
a[i][j]=a[i-1][j-1]+a[i-1][j];
for(i=0;i<N;i++)
{
for(j=0;j<i+1;j++)
printf("%-5d",a[i][j]);
printf("\n");
}
}

xt6_7

/*z238 8
1 1 1 1 1
2 1 1 1 1
3 2 1 1 1
4 3 2 1 1
5 4 3 2 1*/
#include <stdio.h>
#define M 5
main()
{
int i,j,a[M][M];
for(i=0;i<M;i++)
for(j=0;j<M;j++)
if(i<=j) a[i][j]=1;
else a[i][j]=i-j+1;
for(i=0;i<M;i++)
{
for(j=0;j<M;j++)
printf("%2d",a[i][j]);
printf("\n");
}
}

xt6_8

#include <stdio.h>
main()
{
char ch[3],ch1;
gets(ch);
ch1=getchar();
puts(ch);
putchar(ch1);
putchar('\n');
}